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Here, AB = AD in \triangle A B D and AC = AE in \triangle A CE and \angle B A D=\angle E A C .

Then,

Option: 1

BC = DE


Option: 2

BD = AE


Option: 3

Both (a) and (b)


Option: 4

None of the above


Answers (1)

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\\\text{In } \triangle A B C\text{ and } \triangle A D E,\text{ we have} \\\\A B=A D \quad \text { (given) } \\ \\\ {\color{Blue} \angle B A C =\angle B A D+\angle C A D =\angle E A C+\angle C A D =\angle D A E \quad[\because \angle B A D=\angle E A C] } \\\\ A C=A E \quad \text { (given) } \\ \\\therefore \quad \triangle A B C \cong \Delta A D E \quad \text { (SAS-criteria) } \\ \\\text { Hence, } B C=D E \quad( \text { c.p.c.t.) }

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Divya Prakash Singh

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