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If solution of |x+9|>-3 is the set A and the solution of |x+9|< -3 is the set B then set A and set B  are

Option: 1

\mathbb{R},\mathrm{\phi}


Option: 2

\mathbb{R},\mathbb{R}


Option: 3

\phi, \phi


Option: 4

\phi,\mathbb{R}


Answers (1)

best_answer

|x+9|>-3

As modulus for any real value of  (x+9) will always be positive, so it will always be greater than -3.

So,A=\mathbb{R} ( all real numbers)

Also |x+9| can never be less than -3 ,so B=\phi

 

Posted by

Deependra Verma

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