If two chords of a circle are equally inclined to the diameter through their point of intersection, then the chords are equal. (True/False)
True
False
The statement is true, let us see how
Let AB and AC are chord of circle and AOD is a diameter such that ∠ OAB = ∠ OAC
Now, draw OL perpendicular to AB and OM perpendicular to AC
Consider ? OLA and ? OMA
∠ OMA = ∠ OMA
OA = OA
∠ OAM = ∠ OAM
? OLA ≅ ? OMA
This gives, OL = OM
chords AB and AC are equidistant from O
So, AB = AC
Hence, the statement is true