Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Management
  • In the given figure, ABC is a triangle, right angled at B. If

In the given figure,

ABC is a triangle, right angled at B. If BCDE is a square on side BC and ACFG is a square on AC. Then

Option: 1

A D\neq F B


Option: 2

A D=F B


Option: 3

A D=\sqrt2F B


Option: 4

None of the above


Answers (1)

best_answer

\begin{align*} &\text{In } \triangle ACD \text{ and } \triangle FCB, \text{ we have:} \\ &\angle ACD = 90^{\circ} + \angle BCA \\ &\angle FCB = 90^{\circ} + \angle BCA \\ \Rightarrow &\angle ACD = \angle FCB \\ &CA = CF \quad \text{(sides of the same square)} \\ &CD = CB \quad \text{(sides of the same square)} \\ \therefore &\triangle ACD \cong \triangle FCB \quad \text{(by SAS-criteria)} \\ \text{Hence, } &AD = FB \quad \text{(c.p.c.t.)} \end{align*}

Posted by

Deependra Verma

View full answer

Similar Questions

Trending Articles/News

anam-khan

CAT 2025: IIM Calcutta MBA sees widening gender gap, dominance of science students, freshers
anam-khan

‘I got 99.6 percentile in CAT exam but no top IIM called for interview’: What CAT 2025 aspirants should know
anam-khan

CAT 2025: IIM Lucknow assigns 30% weightage to exam for MBA admissions

Latest Question