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  • Let O is the circumcentre of triangle ABC with circumradius 10 cm. Let BC = 16 cm and OD is perpendicular to BC. Then the length of OD isOption: 1</str

Let O is the circumcentre of triangle ABC with circumradius 10 cm. Let BC = 16 cm and OD is perpendicular to BC. Then the length of OD is

Option: 1

6 cm


Option: 2

5 cm


Option: 3

4 cm


Option: 4

None of these


Answers (1)

best_answer

The point of intersection of the perpendicular bisectors of the sides of a triangle is called its circumcenter. The circumcenter is equidistant from all the vertices of the triangle. 

Given that, circumradius = OB = 10 cm

BC = 16 cm

and, BD = DC = 8 cm

we need to find OD

Triangle BOD is right-angle triangle, with a right angle at D

Apply Pythagoras theorem, we get

OD=\sqrt{10^2-8^2}=6\;cm

Posted by

manish painkra

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