Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Management
  • The areas of two similar triangles are 144 cm2 and 64 cm2 respectively. If the median of fi rst triangle is 14.4 cm, find the corresponding median of the other.<div class=

The areas of two similar triangles are 144 cm2 and 64 cm2 respectively. If the median of fi rst triangle is 14.4 cm, find the corresponding median of the other.

Option: 1

9.6 cm


Option: 2

8.8 cm


Option: 3

9.2 cm


Option: 4

None of the above


Answers (1)

best_answer

The ratio of the areas of two similar triangles is equal to the ratio of the squares of their corresponding medians.

\large \begin{array}{l} \therefore \quad \frac{\operatorname{ar}(\Delta A B C)}{\operatorname{ar}(\Delta D E F)}=\frac{A P^{2}}{D Q^{2}} \\ \Rightarrow \quad\left(\frac{A P}{D Q}\right)^{2}=\frac{\operatorname{ar}(\triangle A B C)}{\operatorname{ar}(\Delta D E F)}=\frac{144}{64}=\left(\frac{12}{8}\right)^{2} \\ \Rightarrow \frac{A P}{D Q}=\frac{12}{8} \Rightarrow \frac{14.4}{D Q}=\frac{12}{8} \end{array}

\Rightarrow D Q=\frac{(14.4 \times 8)}{12} cm =(1.2 \times 8) cm =9.6 cm

Posted by

himanshu.meshram

View full answer

Similar Questions

Trending Articles/News

anam-khan

IIM Calcutta: Names of shortlisted candidates for personal interview out; MBA selection process 2025
anam-khan

IIM Bodh Gaya announces MBA admission policy 2025; gives 45% weightage to CAT 2024 score
anam-khan

CAT 2024: Delhi HC junks plea over error in exam results

Latest Question