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  • The base of an isosceles triangle is 8 cm long and each of its equal sides measures 6 cm. Then the area of the triangle is (in cm2)Option: 1

The base of an isosceles triangle is 8 cm long and each of its equal sides measures 6 cm. Then the area of the triangle is (in cm2)

Option: 1

16\sqrt5


Option: 2

25


Option: 3

16


Option: 4

8\sqrt5


Answers (1)

best_answer

Given that,

The base of an isosceles triangle is 8 cm long and each of its equal sides measures 6 cm.

Let ABC be the triangle, with base, BC = 8  cm and AC = AB = 6 cm 

In this case also, we want to know the height of the triangle. Let D be the mid point of BC. and AD is perpendicular to BC. Clearly, ABD is a right angle triangle witj BD = 4 cm

Then, by using Pythagoras theorem, we get  

        AD2 = AB2 - BD2

                   = 62 -  42 = 36 - 16 = 20

So, AD = 2\sqrt5 cm

Now, area of ? ABC = \frac{1}{2} \times \text { base } \times \text { height }=\frac{1}{2} \times 8 \times 2\sqrt5 \mathrm{cm}^{2}=8\sqrt5 \mathrm{cm}^{2}

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Posted by

Deependra Verma

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