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The distance between the centers of an equal circle each of radius 4 cm is 10 cm. The length of transverse common tangent is

Option: 1

4 cm


Option: 2

8 cm


Option: 3

6 cm


Option: 4

None of these


Answers (1)

best_answer

The length of the transverse common tangent is \sqrt{d^2-(r_1+r_2)^2}

d = 10 cm and r_1=r_2=4\;cm

So, The length of the transverse common tangent = \sqrt{10^2-(4+4)^2}=6\;cm

 

Posted by

avinash.dongre

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