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The equatiomn of the circle whose centre is at (2,0) and having radius 3 unit is

Option: 1

x^2+y^2+4x+5=0


Option: 2

x^2+y^2-4x-5=0


Option: 3

x^2+y^2-4y-5=0


Option: 4

x^2+y^2-4x+5=0


Answers (1)

best_answer

Given centre of the circle (h,k) = (2,0)

and radius = 3

equation of circle 

\\\Rightarrow (x-2)^2+(y-0)^2=3^2\\\Rightarrow x^2-4x+4+y^2=9\\\Rightarrow x^2+y^2-4x-5=0

Posted by

HARSH KANKARIA

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