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The lengths of the sides of a cyclic quadrilateral area 1, 3, 5, and 7 units. Then the area of the quadrilateral is (in units2)  

Option: 1

\sqrt{121}


Option: 2

\sqrt{91}


Option: 3

\sqrt{105}


Option: 4

None of these


Answers (1)

best_answer

Given that the lengths of the sides of a cyclic quadrilateral area 1, 3, 5, and 7 units

\\\mathrm{s=\frac{1}{2}(1+3+5+7)=8}\\\mathrm{area=\sqrt{(8-1)(8-3)(8-5)(8-7)}=\sqrt{105}}

 

Posted by

jitender.kumar

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