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The product of 10 consecutive even numbers is always divisible by
Option: 1
$2^{10}$

Option: 2
$3\left(2^9\right)$

Option: 3
$2^{10} \times 10 !$

Option: 4
None of these

Answers (1)

best_answer

The product of 10 even number must be multiple of 10 multiple of 2 hence divisible by $2^{10}$

Posted by

Rakesh

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