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There are three numbers in A.P. whose sum is 24 and product is 480. Find the numbers.

Option: 1

1,5,10


Option: 2

6,8,10


Option: 3

2,5,7


Option: 4

1,5,10


Answers (1)

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Let the three numbers be a-d, a and a+d.

$\begin{aligned} & a-d+a+a+d=24 \\ & \Rightarrow 3 a=24 \\ & \Rightarrow a=8 \\ & (8-d)(8)(8+d)=480\end{aligned}$

$\begin{aligned} & \Rightarrow 64-d^2=60 \\ & \Rightarrow d^2=4 \\ & \Rightarrow d= \pm 2\end{aligned}$

Hence the three numbers are 6, 8 and 10 when d = 2 and the same numbers in reverse order, when$d=-2$.

Posted by

Divya Prakash Singh

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