Two number, both greater than 29, have GCD = 29 and LCM = 4147. The sum of the numbers is:
669
696
766
767
Product of numbers $=29 * 4147$
Let the numbers be $29 a$ and $29 b$.
Then, $29 a * 29 b=(24 * 4147)$
$\Rightarrow>a b=143$.
Now, co-primes with product 143 are (1, 143) and (11, 13).
So, the numbers are $(29 * 1,29 * 143)$ and $(29 * 11,29 * 13)$.
Since both numbers are greater than 29 , the suitable pair is $(29 * 11,29 * 13)$ i.e., $(319,377)$.
Required sum $=(319+377)=696$