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Two number, both greater than 29, have GCD = 29 and LCM = 4147. The sum of the numbers is:

Option: 1

669


Option: 2

696


Option: 3

766


Option: 4

767


Answers (1)

best_answer

Product of numbers $=29 * 4147$

Let the numbers be $29 a$ and $29 b$.

Then, $29 a * 29 b=(24 * 4147)$

$\Rightarrow>a b=143$.

Now, co-primes with product 143 are (1, 143) and (11, 13).

So, the numbers are $(29 * 1,29 * 143)$ and $(29 * 11,29 * 13)$.

Since both numbers are greater than 29 , the suitable pair is $(29 * 11,29 * 13)$ i.e., $(319,377)$.

Required sum $=(319+377)=696$

 

 


 

Posted by

Ritika Kankaria

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