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What is the zeros of the polynomial 6 x^{2}-3-7 x

Option: 1

3/2 and 1/3


Option: 2

2/3 and -1/3


Option: 3

3/2 and -1/3


Option: 4

None of the above


Answers (1)

best_answer

Let the given polynomial denote by p(x)

\begin{aligned} p(x) &=6 x^{2}-3-7 x \\ &=6 x^{2}-7 x-3 \quad \text { [in standard form] } \\ &=6 x^{2}-9 x+2 x-3 \\ &=3 x(2 x-3)+(2 x-3) \\ &=(2 x-3)(3 x+1) \end{aligned}

\begin{aligned} \therefore \quad f(x)=0 & \Rightarrow(2 x-3)(3 x+1)=0 \\ & \Rightarrow 2 x-3=0 \text { or } 3 x+1=0 \\ & \Rightarrow x=\frac{3}{2} \text { or } x=\frac{-1}{3} \end{aligned}

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manish

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