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Which of the following point lies inside the circle x^{2}+y^{2}-2x+2y-16=0

Option: 1

(2,1)


Option: 2

(1,2)


Option: 3

(-2,-2)


Option: 4

All of the above


Answers (1)

best_answer

Equation of circle x^{2}+y^{2}-2x+2y-16=0

(a) (2,1)

2^2+1^2-2\cdot 2+2\cdot 1-16=-13<0

(b) (1,2)

1^2+2^2-2\cdot 1+2\cdot 2-16=-9<0

(c) (-2,-2)

\left(-2\right)^2+\left(-2\right)^2-2\cdot \left(-2\right)+2\cdot \left(-2\right)-16=-8<0

So all the point lies inside the circle

Posted by

manish painkra

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