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  • 10 resistors, each of resistance R are connected in series to a battery of emf E and negligible internal resistance. Then those are connected in parallel to the same battery, the current is increas

10 resistors, each of resistance R are connected in series to a battery of emf E and negligible internal resistance. Then those are connected in parallel to the same battery, the current is increased n times. The value of n is:

Option: 1

10


Option: 2

100


Option: 3

1


Option: 4

1000


Answers (1)

best_answer

\begin{aligned} & I_1=\frac{E}{10 R} \\ & I_2=\frac{E}{R / 10}=\frac{10 E}{R} \\ & \Rightarrow I_2=n I_1 \\ & \Rightarrow \frac{10 E}{R}=n\left(\frac{E}{10 R}\right) \Rightarrow n=100 \end{aligned}

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Deependra Verma

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