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A bar magnet, of magnetic moment M is placed in a magnetic field of induction \mathrm{\underset{B}{\rightarrow}} The torque exerted on it is

Option: 1

\overrightarrow{\mathrm{M}} \cdot \overrightarrow{\mathrm{B}}


Option: 2

-\overrightarrow{\mathrm{M}} \cdot \overrightarrow{\mathrm{B}}


Option: 3

\overrightarrow{\mathrm{M}} \times \overrightarrow{\mathrm{B}}


Option: 4

\overrightarrow{\mathrm{B}} \times \overrightarrow{\mathrm{M}}


Answers (1)

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We know that when a bar magnet is placed in the magnetic field at an angle \theta  then torque acting on the bar magnet (\tau) 
=\mathrm{MB} \sin \theta=\overrightarrow{\mathrm{M}} \times \overrightarrow{\mathrm{B}} \text {. }

Note : This torque \tau  has a tendency to make the axis of the magnet parallel to the direction of the magnetic field.

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