fdfd.PNG A bullet of mass 10 g moving horizontal with a velocity of 400 m sl strikes a wood block of mass 2 kg which is suspended by light inextensible string of length 5 m. As result; the centre of gravity of the block found to rise a vertical distance of 10 cm. The speed of the bullet after it emerges out horizontally from the block will be

Answers (2)

 Apply conservation of momentum

\frac{10}{1000}\times400+0=2V_{1}+\frac{10}{1000}\times V_{2}

4=2V_{1}+0.01V_{2}....(i)

W.E.T\Rightarrow W=\Delta KE

2\times 10\times0.1=\frac{1}{2}\times 2\times V_{1}^{2}

V_{1}=\sqrt{2}=1.4 m/s \rightarrow put\ in (1)

4=2\times 1.4+0.01V_{2}
V_{2}=120 m/s

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