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  • A constant current flows in an R-L circuit. ThenOption: 1 <img alt="\mathrm{V_R=0 \text { and } V_L \neq 0(V=\text { potential difference })}" src="h

A constant current flows in an R-L circuit. Then

Option: 1

\mathrm{V_R=0 \text { and } V_L \neq 0(V=\text { potential difference })}


Option: 2

energy wasted per second in the resistor = energy gained by the inductor per second


Option: 3

\mathrm{V_R=i R / 2 \text { (numerically) }}


Option: 4

\mathrm{V_R \neq 0 \text { and } V_L=0}


Answers (1)

best_answer

\mathrm{\text { When } \mathrm{i}=\text { constant, } \frac{\mathrm{di}}{\mathrm{dt}}=0}

\mathrm{\Rightarrow \text { Induced emf across the inductor }=E_L=-\mathrm{L} \frac{\mathrm{d} \mathrm{l}}{\mathrm{dt}}=0}

 Potential drop across the inductor is zero

\mathrm{\Rightarrow V_L=0}

\mathrm{\text { Therefore potential drop across the resistor }=V_R=i R}

\mathrm{\Rightarrow V_{net}=V_R+V_L=i R}

\mathrm{\text { Electrical power }=\mathrm{P}=\mathrm{i}^2 \mathrm{R}}

\mathrm{\Rightarrow \text { Energy loss per second in the resistor } \alpha \ \mathrm{i}^2 \mathrm{R}}

\mathrm{\text { The energy stored in the inductor }=U_L=\frac{1}{2} \mathrm{Li}^2=\text { constant }}

\mathrm{\Rightarrow \frac{d U_L}{d t}=0}

\mathrm{\Rightarrow \text { The energy gained by the inductor per second }=0}

Posted by

Deependra Verma

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