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  • A copper rod of length 0.19 m is moving with a uniform velocity 10 m/s parallel to a long straight wire carrying current of 5.0 A. The rod itself is perpendicular to wire with its ends at distance

A copper rod of length 0.19 m is moving with a uniform velocity 10 m/s parallel to a long straight wire carrying current of 5.0 A. The rod itself is perpendicular to wire with its ends at distance 0.01 m and 0.2 m from it. The e.m.f induced in rod is (approximately)

Option: 1

20\; \mu V


Option: 2

30\; \mu V


Option: 3

40\; \mu V

 


Option: 4

50\; \mu V


Answers (1)

best_answer

Answer (2)

e=\int_{0.01}^{0.2}vBdx=v\frac{\mu _{0}}{2\pi}i\int_{0.01}^{0.2}\frac{dx}{x}

e=2 \times 10^{-7}\times 5\times10 \log\; e\left [ \frac{0.2}{0.01} \right ]

    =10^{-5}\times2.303 \log _{10}20

     =29.96 \times 10^{-6}V

     \simeq 30\; \mu V

Posted by

Riya

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