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A liquid of mass m and specific heat C is heated to a temperature "2T". Another liquid of mass m/2 and specific heat 2 C is heated to a temperature T . If these two liquids are mixed the resulting temperature of the mixture is 

Option: 1

2T/ 3 


Option: 2

8T/5 


Option: 3

3T/5 


Option: 4

3T/2 


Answers (1)

best_answer

The mixture of two substances -

\theta_{mix}=\frac{m_{1}c_{1}\theta_{1}+m_{2}c_{2}\theta_{2}}{m_{1}c_{1}+m_{2}c_{2}}

- wherein

\theta_{mix}= The temperature of the mixture at equilibrium. 

 T_{mix}= \frac{m_1 C_1 T_1 + m_2 C_2 T_2 }{m_1C_1+m_2C_2 }\\\\\\ = \frac{mc \cdot 2T+ \frac{m}{2}\cdot 2C\cdot T}{mc+m/2 \cdot 2C}\\\\\\ = \frac{3mCT}{2mC} = \frac{3T}{2}

 

Posted by

manish painkra

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