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A parallel plate capacitor is charged from a cell and then isolated from it. A dielectric slab of dielectric constant k is now introduced in the region between the plates, filling half of it. The intensity of field in the dielectric is E, and that in air is E_2, than

Option: 1

E_1=\frac{E_2}{k}


Option: 2

E_1=k E_2


Option: 3

E_1=E_2


Option: 4

E_1=2 E_2


Answers (1)

The potential difference between the plates in both halves is same, and also separation between the plates also same. \mathrm{\therefore E_1=E_2=\frac{V}{d} }
 

Posted by

Kshitij

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