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  • A particle moves in a circle of radius 5 cm with constant speed and time period 0.2s. The acceleration of the particle i

A particle moves in a circle of radius 5 cm with constant speed and time period 0.2\pis. The acceleration of the particle is:

Option: 1

5 m/s2


Option: 2

15 m/s2


Option: 3

25 m/s2


Option: 4

36 m/s2


Answers (1)

best_answer

 

 v = R \omega = R\frac{2\pi }{T} = \frac{2\pi R}{T}

v= \frac{2\pi \times 0.05}{0.2\pi } = 0.5\ ms^{-1}

\therefore a = \frac{v^{2}}{R} = \frac{\left ( 0.5\right )^{2}}{5\times 10^{-2}} = 5\ ms^{-2}

Posted by

himanshu.meshram

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