A plank is placed on a solid cylinder which rolls on a horizontal surface.The two are of equal mass.There is no slipping in any of the surfaces in contact.Find the ratio of kinetic energy of plank and cylinder.

Answers (2)

 

Kinetic energy of plank: \frac{1}{2} (m)((2v)^2)

Kinetic energy of cylinder is \frac{1}{2} (m)((v)^2) +\frac{1}{2}IW^2

where W is angular velocity

So kinetic energy of cylinder is \frac{1}{2} (m)((v)^2) +\frac{1}{2}\frac{mR^2}{2}(\frac{V}{R})^2=\frac{3}{4}(mv^2)

   ratio=\frac{0.5m(2v)^2}{0.5mv^2+0.5\frac{mr^2v^2}{2r^2}}=8:3???????

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