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A potential barrier V volts exists across P-N junction. The thickness of the depletion region is ‘d’. An electron with velocity ‘v_{0}’ approaches P-N junction from P side. The velocity of electron crossing the junction is

Option: 1

\sqrt{v_{0}^{2}+\frac{2Ve}{m}}


Option: 2

\sqrt{v_{0}^{2}-\frac{2Ve}{m}}


Option: 3

v_{0}

 


Option: 4

\sqrt{\frac{2Ve}{m}}


Answers (1)

best_answer

Answer (1)

direction of electric field across barrier will be from N type to P type therefore force will be in the direction of velocity.

V^{2}=u^{2}+2\; as

v=\sqrt{v_{0}^{2}+\frac{2eV}{m}}

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Nehul

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