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A prism of refractive index '\mu ' and refracting angle 'A ' is placed in the minimum deviation position. If the angle of minimum deviation is A, then the value of A in term of '\mu ' is

Option: 1

\sin ^{-1}\left ( \frac{\mu }{2} \right )


Option: 2

\sin ^{-1}\sqrt{\frac{\mu -1}{2}}


Option: 3

2\cos ^{-1}\left ( \frac{\mu }{2} \right )

 


Option: 4

\cos ^{-1}\left ( \frac{\mu }{2} \right )


Answers (1)

best_answer

Answer (3)

\mu =\frac{\sin\left ( \frac{A+A}{2} \right )}{\sin\left ( \frac{A}{2} \right )}

\Rightarrow \mu =2 \cos\frac{A}{2}

A=2 \cos^{-1}\left ( \frac{\mu }{2} \right )

 

Posted by

Devendra Khairwa

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