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  • A refrigeration tank holding 5 litres of gas with molecular formula  at 298 Kand 3 atm pre

A refrigeration tank holding 5 litres of gas with a molecular formula C_2Cl_2 F_4 at 298 K and 3 atm pressure developed a leak. When the leak was discovered and repaired, the tank had lost 76 g of the gas. What was the pressure of the gas remaining in the tank at 298 K?

Answers (1)

best_answer

Given- 

  • Initial pressure = 3 atm
  • Volume = 5 litres
  • Temperature = 298 K
  • Mass of gas lost = 76 g
  • Molecular formula = C2Cl2F4 , Molar mass= (2 × 12) + (2 × 35.5) + (4 × 19)=171 g/mol
  • Gas constant R = 0.0821 L·atm/mol·K

$$
\text {Initial moles} = \frac{P × V} {R × T}= \frac {3 × 5} {0.0821 × 298}≈ 0.612 mol
$$ $$
\text {Moles lost}= \frac{76} {171} ≈ 0.444 mol
$$ $$
\text {Moles remaining} = 0.612 – 0.444 = 0.168 mol
$$ $$ 
\text{New pressure }= \frac{n × R × T} {V} 
$$ $$
P_{new} = \frac {0.168 × 0.0821 × 298} {5} = 0.82 atm
$$

Therefore, the pressure of the gas remaining in the tank is approximately 0.82 atm.

Posted by

Saniya Khatri

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