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A rod fixed at both end is heated then thermal stress developed is ( \alpha = coefficient of linear expasion
y = youngs modulus of elasticity)
 

Option: 1

Y\alpha \Delta T

 

 

 


Option: 2

\frac{\alpha \Delta T}{Y}


Option: 3

\frac{Y \Delta T}{\alpha }


Option: 4

\frac{ \Delta T}{\alpha Y}


Answers (1)

best_answer

As we learned

 

Change in Length -

\Delta L=L_{0}(\alpha \Delta T)

 

- wherein

\Delta L=L-L_{0}

L-L_{0}=Change in length

\Delta T=T-T_{0}

T-T_{0}= Change in temperature

 

 

\Delta L = L\alpha \Delta T

Thermal strain  = \frac{\Delta L}{L}=\alpha \Delta T

Thermal stress = Y\times Thermal strain

Y\alpha \Delta T

Posted by

manish

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