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  • A set of n resistors each of resistance R are connected in series to a battery of emf E and internal resistance R then a current I is observed to flow. If these

A set of n resistors each of resistance R are connected in series to a battery of emf E and internal resistance R then a current I is observed to flow. If these n resistors are connected in parallel to same battery. It is observed that current increased by 5 times then the value of n will be

Option: 1

10


Option: 2

15


Option: 3

5


Option: 4

8


Answers (1)

best_answer

Answer (3)

I=\frac{E}{R+nR}

I_{1}=\frac{E}{R+\frac{R}{n}}

I_{1}=5I

I_{1}=\frac{E}{R+\frac{R}{n}}=I=\frac{E}{R+nR}

R+nr=5R+\frac{5R}{n}

nR-\frac{5R}{n}-5R=0

n^{2}R-4nR-5R=0

n=\frac{4R\pm \sqrt{16R^{2}+20R^{2}}}{2R}

   =\frac{4R+6R}{2R}

   =5

Posted by

Pankaj Sanodiya

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