# A spherical drop of capacitance 1 mu F is broken into eight drops of equal radius. Then, the capacitance of each small drop is

$\frac{4\pi R^3}{3}=8\frac{4\pi r^3}{3}\\r=R/2\\C=4\pi\varepsilon _0r=4\pi\varepsilon _0R/2=0.5\mu F$