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  • A spherical planet has a mass MP and diameter DP. A particle of mass m falling freely near the surface of this planet will experience an acceleration due to gravity, equal to:

A spherical planet has a mass MP and diameter DP. A particle of mass m falling freely near the surface of this planet will experience an acceleration due to gravity, equal to:

Option: 1

\frac{4GM_p}{D_p^{2}}


Option: 2

\frac{GM_pm}{D_p^{2}}


Option: 3

\frac{GM_p}{D_p^{2}}


Option: 4

\frac{4GM_pm}{D_p^{2}}


Answers (1)

best_answer

\\ Force \\ \\ F=\frac{G M_{e} m}{R^{2}}$ \\ Here, \\ $F=\frac{G M_{p} m}{\left(D_{p} / 2\right)^{2}}$ \\ $F=\frac{4 GM _{ p } m }{ D _{ p }^{2}}$ \\ $F=m a$ \\ Acceleration due to gravity \\ $a =\frac{ F }{ m }=\frac{4 GM _{ P }}{ D _{ P }^{2}}

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Divya Prakash Singh

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