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Q.34) AB is a part of an electrical circuit (see figure). The potential difference " $V_A-V_B$ ", at the instant when current $1=2 \mathrm{~A}$ and is increasing at a rate of 1 amp second is:
A) 10 volt
B) 5 volt
C) 6 volt
D) 9 volt
Answers (1)
$V_B - V_A = -L \frac{di}{dt} - V - iR$
$V_B - V_A = (-1 \times 1) - 5 - (2 \times 2)$
$V_A - V_B = 10 $ volt
Hence, the answer is the option 1
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