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  • ABCD is a rectangular loop made of uniform wire. The length AD=BC=1cm.

ABCD is a rectangular loop made of uniform wire. The length AD=BC=1cm. The sides AB and DC are long as compared to the other two sides. Find the magnetic force per unit length of the wire DC due to the wire AB, If the ammeter reads 10A.

Option: 1

5 \times 10^{-4} \mathrm{~N} / \mathrm{m}


Option: 2

25 \times 10^{-4} \mathrm{~N} / \mathrm{m}


Option: 3

5 \times 10^{-5} \mathrm{~N} / \mathrm{m}


Option: 4

None


Answers (1)

best_answer

By symmetry each of the wire AB and BC carries a current of 5A.

\frac{d F}{d t}=\frac{\mu_0 i_1 i_2}{2 \pi d}

=\frac{\left(2 \times 10^{-7} \mathrm{TmA}^{-1}\right)(5 \mathrm{~A})(5 \mathrm{~A})}{\left(1 \times 10^{-2} \mathrm{~m}\right)}

\begin{aligned} & =\frac{50 \times 10^{-7}}{10^{-2}} \mathrm{~N} / \mathrm{m} \\ & =5 \times 10^{-4} \mathrm{~N} / \mathrm{m} \end{aligned}

Posted by

Ritika Harsh

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