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According to Bragg's formula, what is the path difference between electrons scattered from adjacent crystal planes?

 

Option: 1

\Delta x=2 d \sin \theta \\


Option: 2

\Delta x=n \lambda \\


Option: 3

\Delta x=d \sin \theta \\


Option: 4

\Delta x=\frac{n \lambda}{2} n \theta


Answers (1)

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According to Bragg's formula, the path difference between electrons scattered from adjacent crystal planes is given by \Delta x=2 d \sin \theta,where d is the distance between diffracting planes and \theta  is the angle between the incident rays and the surface of the crystal.

 

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Rakesh

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