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Among the following what is the energy of a photon with a wavelength of 450 nm?

 

Option: 1

2.76 \mathrm{eV}


Option: 2

2.76 \times 10^{-19} \mathrm{~J}


Option: 3

4.4 \mathrm{eV}


Option: 4

4.42 \times 10^{-19} \mathrm{~J}


Answers (1)

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Given, the wavelength of the photon is \lambda=450 \mathrm{~nm}=450 \times 10^{-9} \mathrm{~m}

The energy of the photon is given by the formula E=\frac{hc}{\lambda}where h is Planck's constant and c is the speed of light.

Substituting the values, we get:

E=\frac{h c}{\lambda}=\frac{\left(6.626 \times 10^{-34} \mathrm{~J} \mathrm{~s}\right)\left(3.0 \times 10^8 \mathrm{~m} / \mathrm{s}\right)}{450 \times 10^{-9} \mathrm{~m}}=4.42 \times 10^{-19} \mathrm{~J}

Therefore, the energy of the photon with a wavelength of 450 nm is

4.42 \times 10^{-19} \mathrm{~J}

 

Posted by

Sanket Gandhi

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