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Amongst \left [ Co(ox)_{3} \right ]^{3-}, [CoF_{6}]^{3-} and [Co(NH_{3})_{6}]^{3+}

Option: 1

\left [ Co(ox)_{3} \right ]^{3-}and [CoF_{6}]^{3-}  are paramagnetic and [Co(NH_{3})_{6}]^{3+} is diamagnetic.


Option: 2

\left [ Co(ox)_{3} \right ]^{3-} and [Co(NH_{3})_{6}]^{3+} are paramagnetic and [CoF_{6}]^{3-} is diamagnetic.


Option: 3

\left [ Co(ox)_{3} \right ]^{3-} and [Co(NH_{3})_{6}]^{3+}are diamagnetic and [CoF_{6}]^{3-} is paramagnetic


Option: 4

[Co(NH_{3})_{6}]^{3+} and  [CoF_{6}]^{3-}  are paramagnetic and \left [ Co(ox)_{3} \right ]^{3-} is diamagnetic


Answers (1)

best_answer

 

Dimagnetic Compound -

The complex in which central atom has not any unpaired electrons are known as Diamagnetic compound.

- wherein

Ex. \left [ Ni\left ( CO \right ) _{4}\right ],\left [ Ni\left ( CN \right ) _{4}\right ]^{2-}

Paramagnetism -

The complex in which central atom has unpaired electrons are known as Paramagnetic Compounds.

- wherein

Ex.[Mn(CN)6]3-

 

Weak field Ligand -

These are the ligands which do not pair the electron in inner d-orbital.

- wherein

For example: N_{2}O, F^{-}, Cl^{-} etc    

-

\left [ Co(ox)_{3} \right ]^{3-} , 3d^{6} 

All electrons are paired, so diamagnetic.

[Co(NH_{3})_{6}]^{3+}, 3d^{6}             

All electrons are paired, so diamagnetic.

F- is a weak ligand  [CoF_{6}]^{3-} , 3d^{6}     

It contains four unpaired electrons, so it is paramagnetic.

Therefore, Option(3) is correct.

Posted by

chirag

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