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  • An ac voltage is applied to a resistance R and an inductor L in series. If R and the inductive reactance both are equal to 4 <img alt="\Omega" src="https://entrancecorner.oncodecogs.com/gif.la

An ac voltage is applied to a resistance R and an inductor L in series. If R and the inductive reactance both are equal to 4 \Omega, the phase difference between the applied voltage and the current in the circuit is:

Option: 1

zero


Option: 2

\frac{\pi}{6}


Option: 3

\frac{\pi}{4}


Option: 4

\frac{\pi}{2}


Answers (1)

best_answer

 

 phase difference \Phi =cos^{-1}\frac{R}{Z}

\Phi =cos^{-1}\left ( \frac{4}{\sqrt{4^{2}+4^{2}}} \right )=\cos ^{-1}\left ( \frac{1}{\sqrt{2}} \right )

\Phi =\frac{\pi}{4}

Posted by

Irshad Anwar

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