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  • An alpha particle is accelerated through a potential difference of . Its Kinet

An alpha particle is accelerated through a potential difference of \mathrm{10^6 volt }. Its Kinetic energy will be -

Option: 1

1 \mathrm{MeV}


Option: 2

2 \mathrm{MeV}


Option: 3

4 \mathrm{MeV}


Option: 4

8 \mathrm{MeV}


Answers (1)

best_answer

kinetic energy = charge \mathrm{ \times } Applied voltage.

= \mathrm{ 2 e \times 10^6 \mathrm{~J} }
Divide by charge of electron thew value will be \mathrm{ Mev. }

\mathrm{ \begin{aligned} \text { LE. } & =\frac{2 e}{e} \times 10^6 \mathrm{EV} \\ & =2 \times 10^6 \mathrm{eV} \\ & =2 \mathrm{MeV} \quad \text { Ans. } \end{aligned} }

Posted by

Ajit Kumar Dubey

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