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An ammeter A of finite resistance and a resistor R are joined is series to an ideal cell C.A Potentiometer P is joined in parallel to R. The ammeter reading is \mathrm{I_0} and the potentiometer reading is \mathrm{V_0 }. P is now replaced by a voltmeter of finite resistance. The ammeter reading now is I and the voltmeter reading is V. Then

 

Option: 1

\mathrm{I>I_0, V<V_0}


Option: 2

\mathrm{I>I_0, V>V_0}


Option: 3

\mathrm{I=I_0, V<V_0}


Option: 4

\mathrm{I<I_0, V> V_0}


Answers (1)

best_answer

Effective resistance of R and V is less than effective resistance R and P, hance p.d. across voltmeter (or R ) is less than previous value


Also overall resistance decreases, so overall current increase, hence reading of ammeter increase

Posted by

Shailly goel

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