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  • An electric dipole with dipole moment <img alt="\frac{p_0}{\sqrt{2}}(\hat{i}+\hat{j})" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cfrac%7Bp_0%7D%7B%5Csqrt%7

An electric dipole with dipole moment \frac{p_0}{\sqrt{2}}(\hat{i}+\hat{j}) is held fixed at the origin O in the presence of an uniform electric field of magnitude E_0. If the potential is constant on a circle of radius R. Centered at origin.

Option: 1

Total E-freed at point A is \vec{E}_A=\sqrt{2} E_0(\hat{i}+\hat{j})


Option: 2

if R>>dipole size, the \overrightarrow{E_B}=0


Option: 3

{\rho} =\sqrt{\frac{\rho_0}{4 \pi \epsilon_0 E_0}}


Option: 4

E-field at every point inside circle is zero


Answers (1)

At B, \vec{E} due to dipole is tangential.

So \vec{E}_{\text {other }}=\frac{1}{4 \pi C_0} \cdot \frac{\rho_0}{R^3} \cdot\left\{\frac{\hat{i}+\hat{j}}{\sqrt{2}}\right\}

\vec{E}_{\text {other }}=\frac{1}{4 \pi \epsilon_0} \cdot \frac{\rho_0}{R^3} \cdot\left\{\frac{\hat{i}+\hat{j}}{\sqrt{2}}\right\}

If the other field also had a component in radial direction, then this component would contribute to the net tangential component at A.

Hence option (b).

Posted by

Ramraj Saini

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