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An electron of mass' m ' and charge ' e ' initially at rest gets accelerated by a constant electric field E. The rate of change of de-Broglie wavelength of this electron at time t, ignoring relativistic effects, is-

Option: 1

-\frac{h}{e E t^2}


Option: 2

-\frac{e h t}{E}


Option: 3

-\frac{m h}{e E t^2}


Option: 4

-\frac{h}{e E}


Answers (1)

best_answer

Using newton's equation of motion -
v=u+a t
\mathrm{ we \, \, have, k=0+\frac{e \epsilon}{h} t \Rightarrow u=\frac{e \epsilon}{m} \cdot t } \\ {Hence, \lambda=\frac{h}{m u}=\frac{h m}{m e t t} \Rightarrow \frac{h}{e E t} }
\mathrm{ \therefore \frac{d \lambda}{d t}=\frac{h}{e \epsilon} \times(-1) t^{-2} \Rightarrow \frac{d \lambda}{d t}=-\frac{h}{e E t^2} \text { Ans } }

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chirag

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