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An element having an atomic radius of 0.14 nm crystallizes in an fcc unit cell. What is the length of a side of the cell ?

Option: 1

0.56 nm


Option: 2

0.24 nm


Option: 3

0.96 nm


Option: 4

0.4 nm 


Answers (1)

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For fcc unit cell, a = 2\sqrt{2}.r
Here, a is the edge length and r is the atomic radius (0.144 nm).
a = 2\sqrt{2} \times 0.14 = 0.407\ nm

Hence, the length of a side of a cell is 0.407 nm.

Posted by

Divya Prakash Singh

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