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An e.m.f. of 5 millivolt is induced in a coil when in a nearby placed another coil, the current changes by 5 ampere in 0.1 second. The coefficient of mutual induction between the two coils will be :

Option: 1

 1 Henry


Option: 2

0.1 Henry


Option: 3

0.1 mH


Option: 4

0.001 millihenry


Answers (1)

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\mathrm{\begin{aligned} e=-M & \frac{d i}{d t} \\ & \Rightarrow 5 \times 10^{-3}=-M \frac{5}{0.1} \\ & \Rightarrow M=\frac{5 \times 10^{-3} \times 0.1}{5} \quad \text { (numerically) } \\ & =10^{-4} \mathrm{H}=0.1 \mathrm{mH} . \end{aligned}}

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jitender.kumar

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