An impulse is applied to a ring of mass m along the line passing through its centre.The ring is placed on a rough horizontal surface.What is the linear velocity of the centre of ring once it starts rolling without slipping.

Answers (1)

The linear velocity of the centre of the ring once it starts rolling without slipping is:

\tau =I\alpha\\\tau=fr=\mu mgr\\\Rightarrow \alpha =\frac{\mu g}{r}\\\omega _0=\omega _0+\alpha t=\frac{\mu gt}{r}\\ring\ stop\ sliding\ when\ v=\omega r\\v_0-\mu gt=\frac{\mu gt}{r}r\\v_0=2\mu gt\\v_0=p/m\ t=\frac{p}{2\mu mg}\\v=v_0-\mu gt=2\mu g\frac{p}{2\mu mg}-\mu g\frac{p}{2\mu mg}=\frac{p}{2m}

Most Viewed Questions

Preparation Products

Knockout NEET 2024

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Unlimited Mock Tests and Personalized Analysis Reports, Faculty Support.

₹ 29999/- ₹ 24999/-
Buy Now
Knockout NEET 2025

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 45000/-
Buy Now
Knockout NEET (One Month)

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Unlimited Mock Tests and Personalized Analysis Reports.

₹ 7999/- ₹ 4999/-
Buy Now
Knockout NEET 2023 (One Month)

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Unlimited Mock Tests and Personalized Analysis Reports.

₹ 13999/- ₹ 6999/-
Buy Now
Knockout NEET (Three Months Subscription)

- AI Coach Study Modules, - Unlimited Mock Tests, - Study Improvement Plan.

₹ 5999/- ₹ 4499/-
Buy Now
Boost your Preparation for NEET 2021 with Personlized Coaching
 
Exams
Articles
Questions