Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • An impulse is applied to a ring of mass m along the line passing through its centre.

An impulse is applied to a ring of mass m along the line passing through its centre.The ring is placed on a rough horizontal surface.What is the linear velocity of the centre of ring once it starts rolling without slipping.

Answers (1)

The linear velocity of the centre of the ring once it starts rolling without slipping is:

\tau =I\alpha\\\tau=fr=\mu mgr\\\Rightarrow \alpha =\frac{\mu g}{r}\\\omega _0=\omega _0+\alpha t=\frac{\mu gt}{r}\\ring\ stop\ sliding\ when\ v=\omega r\\v_0-\mu gt=\frac{\mu gt}{r}r\\v_0=2\mu gt\\v_0=p/m\ t=\frac{p}{2\mu mg}\\v=v_0-\mu gt=2\mu g\frac{p}{2\mu mg}-\mu g\frac{p}{2\mu mg}=\frac{p}{2m}

Posted by

Safeer PP

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

UP NEET UG counselling 2025 registration begins; 78 candidates debarred from MBBS, BDS admissions
anam-khan

UP NEET counselling 2025 round 1 registration starts today at 2 pm; fee payment last date July 28
anam-khan

Jammu and Kashmir NEET UG Counselling 2025 registration begins for MBBS, BDS; apply by July 22

Latest Question