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An inductor coil of inductance L is divided into two equal parts and both parts are connected in parallel. The net inductance is :

Option: 1

L


Option: 2

2L


Option: 3

\mathrm{\mathrm{L} / 2}


Option: 4

\mathrm{\mathrm{L} / 4}


Answers (1)

best_answer

\mathrm{\because \quad \mathrm{L}=\mu \mathrm{n}^2 \ell \mathrm{A}}

Hence inductance of each part = \mathrm{\mathrm{L} / 2}

When connected in parallel, the equivalent inductance \mathrm{=\frac{(L / 2) \times(L / 2)}{(L / 2)+(L / 2)}=\frac{L}{4}}

Posted by

Rishabh

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