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  • Answer please! A rectangular coil of length 0.12 m and width 0.1 m having 50 turns of wire is suspended vertically in a uniform magnetic field of strength 0.2 Weber/m2. The coil carries a current of 2 A. If the plane of the coil is inclined at an ang

A rectangular coil of length 0.12 m and width 0.1 m having 50 turns of wire is suspended vertically in a uniform magnetic field of strength 0.2 Weber/m2. The coil carries a current of 2 A. If the plane of the coil is inclined at an angle of 30° with the direction of the field, the torque required to keep the coil in stable equilibrium will be :

  • Option 1)

    0.20 Nm

  • Option 2)

    0.24 Nm

  • Option 3)

    0.12 Nm

  • Option 4)

    0.15 Nm

 

Answers (1)

best_answer

As learnt in concept

Deflecting torque -

T_{def}=NBiAsin heta

heta =90^{circ}

T_{def}=NBiA

- wherein

Deflecting torque always has the maximum value 

 

 T=NIASin\theta=SO\times 20\times 0.12\times 0.2\times\frac{\sqrt{3}}{2}

T=0.20 N.mt


Option 1)

0.20 Nm

This is correct answer

Option 2)

0.24 Nm

This is incorrect answer

Option 3)

0.12 Nm

This is incorrect answer

Option 4)

0.15 Nm

This is incorrect answer

Posted by

Plabita

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