Q

# Answer please! A rectangular coil of length 0.12 m and width 0.1 m having 50 turns of wire is suspended vertically in a uniform magnetic field of strength 0.2 Weber/m2. The coil carries a current of 2 A. If the plane of the coil is inclined at an ang

A rectangular coil of length 0.12 m and width 0.1 m having 50 turns of wire is suspended vertically in a uniform magnetic field of strength 0.2 Weber/m2. The coil carries a current of 2 A. If the plane of the coil is inclined at an angle of 30° with the direction of the field, the torque required to keep the coil in stable equilibrium will be :

• Option 1)

0.20 Nm

• Option 2)

0.24 Nm

• Option 3)

0.12 Nm

• Option 4)

0.15 Nm

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As learnt in concept

Deflecting torque -

$T_{def}=NBiA\sin \theta$

$\theta =90^{\circ}$

$T_{def}=NBiA$

- wherein

Deflecting torque always has the maximum value

T=NIASin$\theta=SO\times 20\times 0.12\times 0.2\times\frac{\sqrt{3}}{2}$

T=0.20 N.mt

Option 1)

0.20 Nm

Option 2)

0.24 Nm

Option 3)

0.12 Nm