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In an electromagnetic wave in free space the root mean square value of the electric field is E_{rms}=6V/m. The peak value of the magnetic field is:-

  • Option 1)

    2.83\times 10^{-8}T

  • Option 2)

    0.70\times 10^{-8}T

  • Option 3)

    4.23\times 10^{-8}T

  • Option 4)

    1.41\times 10^{-8}T

 

Answers (1)

best_answer

As we learnt in 

Relation between Eo and Bo -

E_{o}=c.B_{o}

- wherein

E_{o}= Electric field amplitude

B_{o} = Magnetic field amplitude

C= Speed of light in vacuum

 

 Erms=6 V/m

peak value E_{o}=E_{rms.\sqrt{2}}=(1.41)6\:V/m =8.46\:V/m

magneitc field peak value B_{o}=\frac{8.46}{3\times 10^{8}}T=2.82\times 10^{-8}T


Option 1)

2.83\times 10^{-8}T

Correct

Option 2)

0.70\times 10^{-8}T

Incorrect

Option 3)

4.23\times 10^{-8}T

Incorrect

Option 4)

1.41\times 10^{-8}T

Incorrect

Posted by

prateek

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