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Four electric charges +q, +q, -q and -q are placed at the corners of a square of side 2L (see figure). The electric potential at point A, midway between the two charges +q and +q, is 

  • Option 1)

    \frac{1}{4\pi \epsilon _{0}}\frac{2q}{L}(1+ \sqrt 5)

  • Option 2)

    \frac{1}{4\pi \epsilon _{0}}\frac{2q}{L}(1+\frac{1}{ \sqrt 5})

  • Option 3)

    \frac{1}{4\pi \epsilon _{0}}\frac{2q}{L}(1-\frac{1}{ \sqrt 5})

  • Option 4)

    zero

 

Answers (1)

best_answer

 

Potential of a System of Charge -

V=frac{kq_{1}}{r_{1}}+kfrac{q_{2}}{r_{2}}+frac{kleft ( -q_{3} 
ight )}{r_{3}}+cdots

- wherein

 

 V=\sum V_{i} =\frac{Kq}{L}+\frac{Kq}{L}+\frac{-Kq}{\sqrt{\left ( 2L \right )^{2}}+L^{2}}+\frac{-Kq}{\sqrt{\left ( 2L \right )^{2}}+L^{2}}

V= \frac{Kq}{L}\left [ 2-\frac{2}{\sqrt{5}} \right ] V= \frac{Kq}{L}\left [ 2-\frac{2}{\sqrt{5}} \right ] = \frac{1}{4\varepsilon _{0}}.\frac{29}{L}\left [ 1-\frac{1}{\sqrt{5}} \right ]


Option 1)

\frac{1}{4\pi \epsilon _{0}}\frac{2q}{L}(1+ \sqrt 5)

Incorrect

Option 2)

\frac{1}{4\pi \epsilon _{0}}\frac{2q}{L}(1+\frac{1}{ \sqrt 5})

Incorrect

Option 3)

\frac{1}{4\pi \epsilon _{0}}\frac{2q}{L}(1-\frac{1}{ \sqrt 5})

Correct

Option 4)

zero

Incorrect

Posted by

Aadil

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