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Q

The dimension of $\frac{1}{2}\epsilon _{o}E^{2}$ where $\varepsilon _{o}$ is permittivity of free space and E is electric field, is:

• Option 1)

ML2T-2

• Option 2)

ML-1T-2

• Option 3)

ML2T-1

• Option 4)

MLT-1

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As we learnt in

Dimension -

The power to which fundamental quantities must be raised in order to express the given physical quantities.

-

$^{u}\epsilon =\frac{1}{2}\epsilon_{\circ}E^{2}$

$^{u}\epsilon =\frac{Energy}{Volume}=\frac{ML^{2}T^{-2}}{L^{3}}=ML^{-1}T^{-2}$

Option 1)

ML2T-2

Incorrect

Option 2)

ML-1T-2

Correct

Option 3)

ML2T-1

Incorrect

Option 4)

MLT-1

Incorrect

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