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Answer please! - Physical World & Measurement - NEET

The dimension of \frac{1}{2}\epsilon _{o}E^{2} where \varepsilon _{o} is permittivity of free space and E is electric field, is:

  • Option 1)

    ML2T-2

  • Option 2)

    ML-1T-2

  • Option 3)

    ML2T-1

  • Option 4)

    MLT-1

 
Answers (1)
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As we learnt in

Dimension -

The power to which fundamental quantities must be raised in order to express the given physical quantities.

-

 

 ^{u}\epsilon =\frac{1}{2}\epsilon_{\circ}E^{2}

^{u}\epsilon =\frac{Energy}{Volume}=\frac{ML^{2}T^{-2}}{L^{3}}=ML^{-1}T^{-2}

 


Option 1)

ML2T-2

Incorrect

Option 2)

ML-1T-2

Correct

Option 3)

ML2T-1

Incorrect

Option 4)

MLT-1

Incorrect

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