(a) H2O2 + O3 \rightarrow H2O + 2O2

(b) H2O2 + Ag2O \rightarrow 2Ag + H2O + O2

Role of hydrogen peroxide in the above reactions is respectively:

  • Option 1)

    oxidizing in (a) and reducing in (b)

  • Option 2)

    reducing in (a) and oxidizing in (b)

  • Option 3)

    reducing in (a) and (b)

  • Option 4)

    oxidizing in (a) and (b)

 

Answers (1)

As we learnt in

Rules for Oxidation Number -

The oxidation number of oxygen in most compounds is -2. There are two exceptions.
In peroxide (H2O2; Na2O2),  the oxidation number is -1.

- wherein

In superoxide e.g. KO2 its oxidation number is -1/2.

 

H2O2 acts as reducing agent in all those reactions in which O2 is evolved. 

Correct option is 3.

 

 


Option 1)

oxidizing in (a) and reducing in (b)

Incorrect

Option 2)

reducing in (a) and oxidizing in (b)

Incorrect

Option 3)

reducing in (a) and (b)

Correct

Option 4)

oxidizing in (a) and (b)

Incorrect

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